Pipe A (489 ft, 2.0 ft diameter) alone contributes approximately how many gallons when calculating distribution system volumes?

Pipe A (489 ft, 2.0 ft diameter) alone contributes approximately how many gallons when calculating distribution system volumes?

• A. 5,000 gallons
• B. 11,500 gallons
• C. 50,000 gallons
• D. 100,000 gallons

Answer: (B)

Volume of a cylindrical pipe is its cross-sectional area times its length. With a diameter of 2 feet, the radius is 1 foot, so the cross-sectional area is π × 1^2 = π square feet. Multiply by the length: 489 ft × π ≈ 1536 cubic feet. Convert to gallons using 1 cubic foot ≈ 7.4805 gallons: 1536 × 7.4805 ≈ 11,500 gallons. So this pipe holds about 11,500 gallons.

Volume of a cylindrical pipe is its cross-sectional area times its length. With a diameter of 2 feet, the radius is 1 foot, so the cross-sectional area is π × 1^2 = π square feet. Multiply by the length: 489 ft × π ≈ 1536 cubic feet. Convert to gallons using 1 cubic foot ≈ 7.4805 gallons: 1536 × 7.4805 ≈ 11,500 gallons. So this pipe holds about 11,500 gallons.